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30v^2-114=0
a = 30; b = 0; c = -114;
Δ = b2-4ac
Δ = 02-4·30·(-114)
Δ = 13680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13680}=\sqrt{144*95}=\sqrt{144}*\sqrt{95}=12\sqrt{95}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{95}}{2*30}=\frac{0-12\sqrt{95}}{60} =-\frac{12\sqrt{95}}{60} =-\frac{\sqrt{95}}{5} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{95}}{2*30}=\frac{0+12\sqrt{95}}{60} =\frac{12\sqrt{95}}{60} =\frac{\sqrt{95}}{5} $
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